C MCQ
MCQ
What will be the output of the C program?
#include
int main()
{
printf(“”%d “”,sizeof(2.5));
printf(“”%d “”,sizeof(2));
printf(“”%d””,sizeof(‘A’));
return 0;
}
- 8 4 4
- 8 4 1
- 4 4 1
- 2.5 2 A
8 4 4
What will be the output of the C program?
#include
int main()
{
float x = 3.14;
double y = 3.14;
printf(“”%f %ff””,x, y);
return 0;
}
- Runtime error
- Compilation error
- 3.140000 3.140000
- 3.140000 3.140000f
3.140000 3.140000f
What will be the output of the C program?
#include
int main()
{
int x = 2;
(x & 1) ? printf(“”true””) : printf(“”false””);
return 0;
}
- Compilation error
- TRUE
- FALSE
- Runtime error
FALSE
What will be the output of the C program?
#include
int main()
{
char num = ‘\010’;
printf(“”%d””, num);
return 0;
}
- 10
- 8
- 10
- 8
8
What will be the output of the C program?
#include
#define x =
int main()
{
int a;
a x 5;
printf(“”%d””,a);
return 0;
}
- Compilation error
- Runtime error
- 5
- program incomplete
5
What will be the output of the C program?
#include
int main(){
int i = -1;
do
{
printf(“”HiDoWhile “”);
}while(i++);
return 0;
}
- Compilation Error
- HiDoWhile
- HiDoWhileHiDoWhie
- HiDoWhile
HiDoWhile HiDoWhile
What will be the output of the C program?
#include
int main(){
while(printf(“”%d””, 5) < 4)
printf(“”Loop “”);
return 0;
}
- Prints Nothing
- 5Loop 5Loop 5Loop 5Loop 5Loop
- 5Loop
- Infinite iterations or Infinite Loop
Infinite iterations or Infinite Loop
What will be the output of the C program?
#include
#define FALSE -1
#define NULL 0
#define TRUE 1
int main(){
if(NULL)
printf(“”NULL””);
else if(FALSE)
printf(“”TRUE””);
else
printf(“”FALSE””);
return 0;
}
- FALSE
- TRUE
- NULL
- Compilation Error
TRUE
What will be the output of the C program?
#include
int main(){
int i = 0, j = 0;
if(i++ == j++)
printf(“”%d %d””, i–, j–);
else
printf(“”%d %d””, i, j);
return 0;
}
- 0 0
- 0 1
- 1 0
- 1 1
1 1
What will be the output of the C program?
#include
#define loop for(;;)
int main()
{
printf(“”DONE””);
loop;
return 0;
}
- Compilation error
- Done
- Program never ends
- None of the above
Program never ends
What will be the output of the C program?
#include
int main()
{
char i = 0;
for(;i>=0;i++);
printf(“”%d””, i);
return 0;
}
- Compilation error
- -128
- 0
- 1
-128
What will be the output of the C program?
#include
int main()
{
int i;
if(scanf(“”%d””,&i)) //if we give input as 0
printf(“”inside if block””);
else
printf(“”inside else block””);
return 0;
}
- Runtime error
- Compilation error
- inside else block
- inside if block
inside if block
What will be the output of the C program?
#include
int main(){
int i = 3, j = 4;
switch(i | j)
{
case 1:
printf(“”inside case 1″”);
break;
case 3:
printf(“”inside case 3″”);
break;
case 4:
printf(“”inside case 4″”);
break;
case 7:
printf(“”inside case 7″”);
break;
}
return 0;
}
- inside case 1
- inside case 3
- inside case 7
- inside case 4
inside case 7
What will be the output of the C program?
#include
#define preprocessor(n) printf (“”macro”” #n “” = %d””, macro##n)
int main(void) {
int macro25 = 47;
preprocessor(25);
return 0;
}
- Compilation error
- macro25 = 47
- macro47 = 25
- Runtime error
macro25 = 47
What is the output of following program?
# include
int main()
{
char str1[] = “”GeeksQuiz””;
char str2[] = {‘G’, ‘e’, ‘e’, ‘k’, ‘s’, ‘Q’, ‘u’, ‘i’, ‘z’};
int n1 = sizeof(str1)/sizeof(str1[0]);
int n2 = sizeof(str2)/sizeof(str2[0]);
printf(“”n1 = %d, n2 = %d””, n1, n2);
return 0;
}
- n1 = 10, n2 = 9
- n1 = 10, n2 = 10
- n1 = 9, n2 = 9
- n1 = 9, n2 = 10
n1 = 10, n2 = 9
In below program, what would you put in place of “?” to print “”Cranesvarsity”?
#include
int main()
{
char arr[] = “”Cranesvarsity””;
printf(“”%s””, ?);
return 0;
}
- arr
- (arr+5)
- (arr+4)
- Not possible
arr
What will be the output of the program?
#include
int addmult(int ii, int jj)
{
int kk, ll;
kk = ii + jj;
ll = ii * jj;
return (kk, ll);
}
int main()
{
int i=3, j=4, k, l;
k = addmult(i, j);
l = addmult(i, j);
printf(“”%d %d””, k, l);
return 0;
}
- 12 12
- No error, No output
- Error: Compile error
- None of above
12 12
What will be the output of the program?
#include
int fun(int i)
{
i++;
return i;
}
int main()
{
int fun(int);
int i=3;
fun(i=fun(fun(i)));
printf(“”%d””, i);
return 0;
}
- 5
- 4
- error
- Garbage value
5
#include
int fun()
{
static int num = 16;
return num–;
}
int main()
{
for(fun(); fun(); fun())
printf(“”%d “”, fun());
return 0;
}
- Infinite loop
- 13 10 7 4 1
- 14 11 8 5 2
- 15 12 8 5 2
14 11 8 5 2
#include
int main()
{
int x = 10;
static int y = x;
if(x == y)
printf(“”Equal””);
else if(x > y)
printf(“”Greater””);
else
printf(“”Less””);
return 0;
}
- compiler error
- equal
- greater
- less
compiler error
Which of the following statement are correct?
(I) The maximum value a variable can hold depends upon its storage class.
(II) By default all variables enjoy a static storage class.
- Only I is correct
- Only II is correct
- Both I & II are correct
- Both I & II are incorrect
Both I & II are incorrect
What will be the output of the following program?
#include
int main()
{
register int i = 2;
static char ch = ‘A’;
auto float j;
int k;
k = ++ch && i;
k = ++ch;
j = i– + ++k * 2;
printf(“%d %f”, k , j);
return 0;
}
- B 3
- 65 138.000000
- 68 138.000000
- A 138
68 138.000000
What will be the output of the following code?
#include< stdio.h>
int main()
{
extern int a=0;
static char j = ‘E’;
printf(“%c %d”, ++j, ++a);
return 0;
}
- E 1
- F 1
- F Garbage
- Compler error
compiler error
What will be the output of the program if the array begins at 65472 and each integer occupies 2 bytes?
#include
int main()
{
int a[3][4]={1,2,3,4,4,3,2,1,7,8,9,0};
printf(“%u,%u”,a+1,&a+1);
}
- 65474, 65488
- 65480, 65488
- 65480, 65496
- 65474, 65476
65480, 65496
Predict output of following program
int main()
{
int i;
int arr[5] = {1};
for (i = 0; i < 5; i++)
printf(“”%d “”, arr[i]);
return 0;
}
- 1 followed by four garbage values
- 1 0 0 0 0
- 1 1 1 1 1
- 0 0 0 0 0
1 0 0 0 0
Predict output of following program
#include
int main()
{
char p;
char buf[10] = {1, 2, 3, 4, 5, 6, 9, 8};
p = (buf + 1)[5];
printf(“”%d””, p);
return 0;
}
- 5
- 6
- 9
- None of the above
9
What will be the output of the program ?
#include
int main()
{
int a[5] = {5, 1, 15, 20, 25};
int i, j, m;
i = ++a[1];
j = a[1]++;
m = a[i++];
printf(“”%d, %d, %d””, i, j, m);
return 0;
}
- 2 1 15
- 1 2 5
- 3 2 15
- 2 3 20
3 2 15
What will be the output of the program?
#include
int main()
{
int arr[5], i=0;
while(i<5)
arr[i]=++i;
for(i=0; i<5; i++)
printf(“”%d, “”, arr[i]);
return 0;
}
- 1 , 2, 3, 4, 5
- Garbage value, 1, 2, 3, 4
- 0, 1, 2, 3, 4
- 2, 3, 4, 5, 6
Garbage value, 1, 2, 3, 4
What will be the output of the C program?
#include
int function();
main()
{
int i;
i = function();
printf(“”%d””, i);
return 0;
}
function()
{
int a;
a = 250;
return 0;
}
- Runtime error
- 0
- 250
- no output
0
What will be the output of the program ?
#include
int main()
{
int arr[1]={10};
printf(“”%d””, 0[arr]);
return 0;
}
- 1
- 10
- 0
- 6
10
#include
int main()
{
while((printf(“”Hello “”))<4)
{
printf(“”The control is inside the while loop””);
}
printf(“”The control is outside the while loop\n””);
return 0;
}
What will be the output of the program ?
- Hello
- Hello The control is outside the while loop
- The control is outside the while loop
- Compliler Error
Hello The control is outside the while loop
int main()
{
int x = 10;
{
int x = 0;
printf(“”%d””,x);
}
return 0;
}
- 10
- Compilation Error
- 0
- Undefined
0
Which programming language is more faster among these?
- Java
- PHP
- C
- Visual Basic
C
int main()
{
int a = printf (“”hello””);
printf(“”%d””, a);
return 0;
} After executing the above program the value of a is:
- 0
- 1
- 5
- Garbage value
5
#include
int main()
{
int n;
for(n = 7; n!=0; n–)
printf(“”n = %d””, n–);
getchar();
return 0;
}
- 7 6 5 4 3 2 1
- 7 5 3 1
- 6 4 2
- Infinite loop
Infinite loop
#include
int main()
{
printf(“”%x””, -1<<1);
getchar();
return 0;
}
- 0x01
- 0x05
- ffffe
- fffffffe
ffffffe
#include
#include
enum {false, true};
int main()
{
int i = 1;
do
{
printf(“”%d\\n””, i);
i++;
if (i < 15)
continue;
} while (false);
return 0;
}
- 1\n
- 1
- Error
- Infinite Loop
1\n
#include
int main()
{
static int i=5;
if(–i){
main();
printf(“”%d “”,i);
}
}
- 5 4 3 2 1
- 4 3 2 1 0
- 0 0 0 0
- Compile time error
0 0 0 0 0
#include
int main()
{
int x;
printf(“”%d””,scanf(“”%d””,&x));
return 1;
}
- 0
- 2
- 3
- 1
1
#include
int main()
{
int i=0;
for(i=0; i<20; i++)
{
switch(i)
{
case 0:
i+=5;
case 1:
i+=2;
case 5:
i+=5;
default:
i+=4;
break;
}
printf(“”%d “”, i);
}
getchar();
return 0;
}
- 14 24
- 10 22
- 16 21
- Compile time error
16 21
#include
int main()
{
printf(“”%p””, main);
getchar();
return 0;
}
- Compile time error
- Run time error
- Address of main
- No output
Address of main
#include
# include
void fun(int *a)
{
a = (int*)malloc(sizeof(int));
}
int main()
{
int *p;
fun(p);
*p = 6;
printf(“”%d\\n””,*p);
return(0);
}
- 6
- Run time error
- Syntatical error
- No output
No output
What will be the output of following?
void main()
{
int const* p = 5;
printf(“”%d””, ++(*p));
}
- 6
- 5
- Garbage Value
- Compiler Error
Compiler Error
What will be the output of following?
#include
int main()
{
int i=0;
i=printf(“”Where there is a will there is way “”);
printf(“”%d\n””,i);
return 0;
}
- Where there is a will there is way 9
- Where there is a will there is way 35
- Where there is a will there is way 34
- Compiler Error
Where there is a will there is way 35
What will be the output of following?
void main()
{
int m, i = 0, j = 1, k = 2;
m = i++ || j++ || k++;
printf(“”%d %d %d %d””, m, i, j, k);
}
- 1 1 2 3
- 1 1 2 2
- 0 1 2 2
- 0 1 2 3
1 1 2 2
What will be the output of following?
void main()
{
int i = 0;
printf(“”%d %d””, i, i++);
}
- 1 0
- 0 1
- 0 0
- 1 1
1 0
What will be the output of following?
#include
#include
void main()
{
printf(“”%d %d””, sizeof(“”program””), strlen(“”program””));
}
- 7 7
- 8 8
- 8 7
- 7 8
8 7
What will be the output of following?
#include
int main()
{
int array[] = {[1] = 1, [0] = 2, [2] = 3 };
printf(“”%d %d %d””, array[0], array[1], array[2]);
return 0;
}
2 1 3
1 3 2
1 0 2
Error
2 1 3
What will be the output of following?
#include
char A()
{
char c = ‘B’;
return c;
}
int main()
{
printf(“”%lu””, sizeof(A()));
return 0;
}
- 0
- Error
- 2
- 1
1
#include
int main()
{
int i=0;
for (;;);
printf(“”INDIA\n””);
return 0;
}
What will be the output for the above program?
- The string “INDIA” is printed one time
- Compilation Error
- The string “INDIA” is printed infiite times
- The string” INDIA” will never be printed
The string" INDIA" will never be printed
What does the following fragment of C-program print?
char c[] = “”GATE2011″”;
char *p =c;
printf(“”%s””, p + p[3] – p[1]) ;
- GATE2011
- E2011
- 11
- 2011
2011
#include
main()
{
int x = 5;
if(x=5)
{
if(x=5) break;
printf(“”Hello””);
}
printf(“”Hi””);
}
- 1
- 1 2
- No output
- Compile error
compiler error
#include
int main()
{
int i,j,return_val=0;
for(i=0,j=4; i < 5 && j < 10 ;i++,j–)
{
printf(“”%d%d “”,i,j);
}
}
- 04 13 22 31 40
- 04 13 22 31 40 5-1 6-2 7-3 8-4 9-5
- 04 13 22 31 40 5-1 6-2 7-3 8-4
- Compliler Error
04 13 22 31 40
#include
int main()
{
int i=0,*s=NULL;
int *ptr = &i;
char str[] = “”Welcome””;
s = str;
while(*s)
printf(“”%c””, *s++);
return 0;
}
- Welcome
- 0
- Wel
- Wo
Wo
If S is an array of 80 characters, then the value assigned to S through the statement scanf(“%s”,S) with input 12345 would be
- “12345”
- nothing since 12345 is an integer
- S is an illegal name for string
- %s cannot be used for reading in values of S
"12345"
A one dimensional array A has indices 1….75.Each element is a string and takes up three memory words. The array is stored starting at location 1120 decimal. The starting address of A[49] is
- 1167
- 1164
- 1264
- 1169
1264
#include
int main()
{
int a=0,b=0,c=0,d=0,e=a,f=b,g=c;
a=b=c=d=5;//e=f=g=5;
printf(“” %d %d %d %d %d %d %d””,a,b,c,d,e,f,g);
return 0;
}
- 5 5 5 5 0 0 0
- 0 0 0 5 0 0 0
- Compilation error
- 5 5 5 5 5 5 5
5 5 5 5 0 0 0
#include
int main()
{
int num=0x12345678;
printf(“”%x\n””,num=num>>1);
return 0;
}
- 91a2b3c
- 1234567
- 2345678
- None of these
91a2b3c
#include
int main()
{
int num=0x82345678;
printf(“”%x\n””,num=num>>1);
return 0;
} What will be the output?
- c11a2b3c
- 411a2b3c
- 8234567
- None of the above
c11a2b3c
#include
void main()
{
char str1[10]=””abyz””;
int i;
for(i=0; i<4; i++)
{
printf(“”%c””,str1[i] – 32);
}
}
- AB
- zyba
- abyz
- ABYZ
ABYZ
